Skip to content

Draw Without Replacement Odds

Put red and blue items in an urn, draw some without putting them back, and see the exact chance of every number of reds: as a reduced fraction, as a percentage, and “at least” or “at most”.

Chance of exactly 2 red

3/10

30 %
Chance of each number of red items
RedsExactlyAt leastAt most
01/10 (10 %)1/11/10
13/5 (60 %)9/107/10
23/10 (30 %)3/101/1

10 equally likely ways to draw 2 from 5 (up to 1000 items).

How it works

  1. Enter the number of red items and blue items in the urn.
  2. Enter how many you draw, without putting any back.
  3. Read the table: the chance of exactly, at least and at most each number of reds.
  4. Copy the table to share the odds.

What people use it for

  • Raffles and draws

    You hold 3 of 50 tickets and 2 prizes are drawn: what is the chance you win at least one?

  • Card and board games

    What are the odds of two aces in a five-card hand taken from the 4 aces and 48 other cards?

  • Classroom and statistics

    Check a hypergeometric exercise with exact integers, not rounded decimals.

Questions

What is the formula?
The chance of exactly k reds in n draws is C(R, k) × C(B, n − k) ÷ C(R + B, n), where C counts combinations, R is the number of reds and B the number of blues. With 3 reds and 2 blues and 2 drawn, both are red in 3 of 10 ways: 3/10.
Why exact fractions?
The counts use whole numbers of any size, so 3/10 is exactly 3/10 and not 0.30000000000000004. The percentage is rounded to 4 decimals for display only.
What if I put the items back?
Then the draws are independent and the odds are different (a binomial law). This page is for draws without replacement, where each draw changes what is left.
Are there limits?
Up to 1,000 items in the urn. You cannot draw more than the urn holds, and a count that cannot happen (for example 3 reds from an urn with 2) shows no row.